Question

A Carnot heat engine receives 600 kJ of heat per cycle from a source at 627°C and rejects heat to a sink at 27°C. The amount of heat rejected to the sink per cycle (rounded off to the nearest integer) in kJ is

Answer 1

Q_H  = 600 kJ, T_H = 627 °C = 627 + 273  = 900 K, T_L = 27 °C + 273 = 300 K

Since the above engine is working on the carnot cycle, Therefore,

Carnot efficiency = Heat engine efficiency

η = η_HE