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Iron forms two chloride containing respectively 56%and 65% of chlorine, calculate the formula and give the name of the chloride .

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Let say formula of iron chlorides which have 56% and 65% chloride are feclx and fecly respectively.

then, molecular weight of fecl2 = (56 + 35.5x)

∴ Percentage of Cl-\(\frac{35.5x}{(56\ +\ 35.5x)}\times100=56\)

⇒ 3550x = 56(56 + 35.5x)

3550x = 3136 + 1988x

1562x = 3136

x = 2

molecular weight of fecly = (56 + 35.5y)

∴ Percentage of cl-\(\frac{35.5x}{(56\ +\ 35.5y)}\times100=65\)

⇒ 3550y = 3640 + 2307.5y

⇒ 1242.5y = 3640

y = 2.929

y = 3

Hence the formula of iron chloride containing 56% and 65% chlorine are fecl2 and fecl3 respectively.

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