LIVE Course for free

Rated by 1 million+ students
Get app now
JEE MAIN 2023
JEE MAIN 2023 TEST SERIES
NEET 2023 TEST SERIES
NEET 2023
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
16 views
ago in Complex Numbers by (33 points)
edited ago by

If \( \alpha \) and \( \beta \) are the roots of the equation \( x^{2}-x+1=0 \), then \( \alpha^{2009}+\beta^{2009}= \) 

(1) -2 

(2) -1 

(3) 1 

(4) 2

Please log in or register to answer this question.

1 Answer

+1 vote
ago by (38.1k points)

x+ 1 = (x + 1)(x− x + 1)

So, since α is a root of x− x + 1 = 0 we have,

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...