# An overhead water tank has three pipes A, B and C attached to it (as shown in figure). The inlet pipes A and B can fill the empty tank

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An overhead water tank has three pipes A, B and C attached to it (as shown in figure). The inlet pipes A and B can fill the empty tank independently in 15 hours and 12 hours respectively. The outlet pipe C alone can empty a full tank in 20 hours. a) For a routine cleaning of the tank, the tank needs to be emptied. If pipes A and B are closed at the time when the tank is filled to two-fifth of its total capacity, how long will pipe C take to empty the tank completely?

b) How long will it take for the empty tank to fill completely, if all the three pipes are opened simultaneously?

c) On a given day, pipes A, B and C are opened (in order) at 5 am, 8 am and 9 am respectively, to fill the empty tank. In how many hours will the tank be filled completely?

OR

Given that the tank is half-full, only pipe C is opened at 6 AM, to empty the tank. After closing the pipe C and an hour’s cleaning time, tank is filled completely by pipe A and B together. What is the total time taken in the whole process?

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a) Pipe C empties 1 tank in 20 h

⇒ 2/5 th tank in 2/5 x 20 = 8 hours

b) Part of tank filled in 1 hour = $\frac 1{15} + \frac 1{12} - \frac1{20} = \frac 1{10}th$

⇒ time taken to fill tank completely = 10 hours

c) At 5 am,

Let the tank be completely filled in ‘t’ hours

⇒ pipe A is opened for ‘t’ hours

pipe B is opened for ‘t−3’ hours

And, pipe C is opened for ‘t−4’ hours

⇒ In one hour,

part of tank filled by pipe A = t/15 th

part of tank filled by pipe B = t−3/15 th

and, part of tank emptied by pipe C = t−4/15 th

Therefore $\frac t{15} + \frac{t-3}{12} - \frac{t-4}{20} =1$

⇒ t = 10.5

Total time to fill the tank = 10 hours 30 minutes

OR

6 am, pipe C is opened to empty 1/2 filled tank

Time to empty = 10 hours

Time for cleaning = 1 hour

Part of tank filled by pipes A and B in 1 hour = $\frac1{15} + \frac 1{12} = \frac 3{20}$th tank

⇒ time taken to fill the tank completely = 20/3 hours

Total time taken in the process = 10 + 1 + 20/3 = 17 hour 40 minutes