Surds in mathematics

Question

find the value of root of 32 - root of 128 + root of 50 and correct the decimal values to 3 digit.

Answer 1

\(\sqrt {32} - \sqrt{128} + \sqrt {50}\)

\(= \sqrt{2\times 16} - \sqrt{2 \times 64} + \sqrt{2 \times 25}\)

\(= \sqrt{2} (4 - 8 + 5)\)

\(= \sqrt2\)

\(= 1.414\)